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Given An Exponential Function For Compounding Interest, A(X) = P(1.04)x, What Is The Rate Of Change?

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Mathematics

OpenStudy (anonymous):

Given an exponential function for compounding interest, A(10) = P(i.04)x, what is the rate of change?

OpenStudy (campbell_st):

find the 1st derivative... thats the rate of change in futurity value A with respect to fourth dimension x

OpenStudy (anonymous):

in this equation, is 1.04 what yous're using as the slope? @nincompoop

OpenStudy (campbell_st):

at present, 1.04 is the base of the exponent

OpenStudy (anonymous):

I still don't sympathize... im pitiful. this chapter confuses me

OpenStudy (campbell_st):

ok... do you know how to differentiate an exponential office...?

OpenStudy (anonymous):

is that where you practise the log?

OpenStudy (campbell_st):

if \[y = e^{f(x)}\] then \[y' = f'(x) \times e^{f(10)}\]

OpenStudy (campbell_st):

nope its not logs...

OpenStudy (anonymous):

yeah I don't know any of this...

OpenStudy (campbell_st):

ok.... take you washed any calculus...?

OpenStudy (anonymous):

no this is algebra 2

OpenStudy (campbell_st):

ok.... then take makes it hard... accept you been given any information such as ten = 0 A = $5000, then x = 10 A = 7401... anything like that?

OpenStudy (nincompoop):

the involvement rate would exist 0.04 or 4%

OpenStudy (nincompoop):

may I, @campbell_st ?

OpenStudy (campbell_st):

ok....lol... I just realised

OpenStudy (nincompoop):

and so we get-go accept to know the formula for compounded involvement in terms of menstruum. future value = present value * (1+ involvement)^(number of menstruum)

OpenStudy (anonymous):

that sounds familiar @nincompoop

OpenStudy (nincompoop):

A(x) = P(1.04)ten A(x) volition be your future value P is the nowadays value (i.04) is your (1 + interest charge per unit) ^x volition be the terms or how many times it will needed to be applied interest charge per unit is your rate of alter considering it determines how much the corporeality will be compounded

OpenStudy (nincompoop):

since you were given P(1.04)^x it means that the involvement would be ane.04 - 1

OpenStudy (anonymous):

just isn't the rate/compound(due north) ? @nincompoop

OpenStudy (campbell_st):

lol... the interest rate is the rate of change... % per annum... or % per year

OpenStudy (bearding):

ohhh okay! I empathise now!

OpenStudy (bearding):

cheers and then much boys :) @campbell_st @nincompoop

OpenStudy (nincompoop):

the exponent x simply determines the period. significant how long volition this compounded involvement will exist practical. 1 year, 2 years ten years etc.

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Source: https://questioncove.com/updates/5308e614e4b022471a66f235

Posted by: ballardloffinds.blogspot.com

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